I found such an interesting circuit in my research on the request of the forum. I didn’t do the circuit, but I’m sending it because I believe it will work. Let’s try to explain the circuit. I will try it in the future. I will share the result with you. I’m always ready to help friends who try the circuit. Wish you success.
Now let’s take a brief look at our circuit and try to explain the working principles. UGN3503 When we examine the data sheet of the Hall effect element, we see that the element works in anolog. That is to say, a voltage is transferred to the amplitude of the magnetic current. Does it not work with this principle in pens ammeters?
UGN3503 undertakes the duty of the bobbin used there . 1mV 1Ampere set. The Trm1 trimpot in the circuit was set for this purpose. Trm2 trimpot is the reset setting. For this setting Pot1 is set to the middle position and the tool is connected to the DMM circuit. The DC 200mV stage is selected. While the measuring head is idle, it is set to 00.0mV on the DMM scale. If your multimeter is in the automatic range, manual 200mV must be selected
UGN3503 Ratiometric Linear Hall Effect Sensor:
Making the measurement head: The measuring system of the two pencil meters have a system that includes the current of the conductor to be measured. In multi-phase measurements, the system works the same.
One of these pairs is measured by measuring the voltage induced on a coil wrapped around it and shown to us as amperes. The outer end is more appropriate for the range that these peninsulas are adjacent to. UGN3503 isplaced. It is connected with a shielded cable to the electronic unit with a suitable connector.
Calibration: The current consumed by an electrical tool is measured by another ammeter. The measurement unit is reset before measurement. A conductor of the determined load is placed between the sides of the measuring unit. 1mV is set to 1mV with trm1. If the current to be measured is DC, the DMM DC200mV is set. If the load is AC, the DMM should be set to AC 200mV . The circuit was not tried. But it should work in principle. If the load is 10A, it should be 10mV.
Achievements to friends who will try.
SCHEMATIC CIRCUIT DIAGRAM:
