# How to Design a 5V Power Supply in Proteus Schematic Circuit Diagram

Today, I’m excited to share a new and highly crucial tutorial: How to Design a 5V Power Supply in Proteus. While this project may seem basic, its significance lies in its foundational role in nearly all contemporary electronic projects. Whenever I embark on a new project, my first step is designing this DC power supply. After all, without a power source, we can’t effectively utilize any of the components.

### Creating a 5V Power Supply

In the process of creating a 5V Power Supply in Proteus ISIS, we will be utilizing the Voltage Regulator IC commonly referred to as 7805. This particular component serves the purpose of regulating or adjusting the voltage level of the supply voltage. It’s worth noting that most batteries available in the market, such as those found in UPS systems, cars, or motorcycles, are standardized at 12 volts. While this voltage is common for various applications, it poses a challenge when dealing with sensitive electronic components designed to operate on a lower voltage, specifically 5 volts.

The issue arises because electronic devices require 5 volts to function properly, whereas the readily available voltage source is 12 volts. To bridge this gap, an intermediate source or a DC Power Supply is required to convert the source voltage (12 volts) into the operating voltage (5 volts). This dilemma is resolved by employing the 7805 IC, which is aptly named the Voltage Regulating IC.

Therefore, in today’s tutorial, we will be designing a 5V power supply that can adjust the Voltage Level, providing us with the desired voltage output. I always emphasize the importance of hands-on practice, as it enhances understanding. I encourage you to try designing it yourself so that you can grasp the practical application of the Voltage Regulator IC. Let’s dive into the process of designing the 5V power supply in Proteus ISIS.

### How to Design a 5V Power Supply in Proteus

• You can download the complete simulation of 5V Power Supply in Proteus by clicking the below link:

https://www.theengineeringprojects.com/Examples/DCPowerSupplyinProteus.rar

• Voltage Regulating IC 7805 has 3 pins.
• Pin # 1 is used as input pin and it is connected to supply voltages. It is marked as (VI). DC +12 volts are applied to this pin.
• Pin # 2 is called common or ground pin. It is marked as (GND). The whole circuit’s common is applied to this pin.
• Pin # 3 is the output pin of 7805. If 12 volts are applied to its input than it automatically generates 5 volts on this pin. This pin is marked as (VO).
• Now, moving towards the designing of the hardware, first of all place all the components in Proteus workspace, as shown in image below:

• In Hardware implementation, first off all apply source voltage (12 volts) to the input pin of 7805 IC. 2 capacitors are also connected in parallel with the source voltage and their ratings are 1000 uf and 100pf respectively.
• On the other side of IC, we also connect 2 capacitors parallel to the gained output voltage (5 volts), and their ratings are 100pf and 100uf respectively. And a LED is also connected in parallel on the load side.
• If you have placed all the components in their perfect place and all the connections are OK, then the resultant proteus simulation will look like as shown in the below image:

• Now if you closely observe the above image then you will notice that Capacitors connected across the 12 volts are of HIGH rating while the Capacitors connected across LED are of LOW rating. The purpose of applying capacitors is to remove noise from our DC voltages. As, we all know that DC voltage source available in market is not that much pure. So, to get pure DC wave Capacitors are connected across it.
• Now when you will run the final simulation then it will look like, as shown in the image given below:

• As you can see that when i ran the simulation. The LED started to glow. Now here is an important thing to note that i have applied a resistance in series with LED. The value of resistance is very low, and very low voltages appear across this resistor. This resistor limits the current and if we directly connect the LED then, their will be chances that the LED may burn out.
• We can justify it as: From ohms law : V=IR, and by rearranging it, we get : I=V/R .
• Now if we remove resistor then R=0, which means: I=V/0 and it lead us to conclude that: I= infinity or maximum in this case. So the only purpose of the resistor is to limit current.

Alright friends, that’s all for today, I hope now you can design a 5V power supply quite easily in Proteus. If you have some queries, then ask in comments. Subscribe us via email to get these tutorials straight in your inbox. In the next tutorial, I have discussed Variable Voltage Modulation using LM317 in Proteus ISIS.

Check Also
Close

Close
Close