Amplifier Circuit DiagramsLCD-LED Display

Noisy LEDs Schematic Circuit Diagram

These days there are many types of intelligent LEDs available. These LEDs flash or change their color, slowly or quickly, and with different color combinations. Those LEDs that gradually change from color to color (so-called rainbow LEDs) were found to be particularly suitable for an alternative application. They happen to produce incredibly complex sounds when they are connected as shown in this circuit.

Noisy LEDs Schematic Circuit Diagram

Potential divider R1/P1 limits the current through the LEDs and has a significant impact on the sound produced. The value can be set between roughly 100 Ω and 100 kΩ. In this circuit, it was achieved using a resistor and a preset. If you want to keep things very simple you can get rid of the preset and experiment a bit with series resistor R1. The circuit works with a single LED, but the addition of more LEDs leads to more interesting sounds because the LEDs end up ‘fighting’ each other for energy. C2 and resistor R2 form a low-pass filter. Start with a value of about 10 nF in order to hear the full range of sounds. For a ‘heavier’ sound you can increase C2 to about 1 µF or even 10 µF. C1 avoids the presence of any DC voltage at the output.

The supply voltage to the circuit can be anywhere between about 4 V and 10 V (depending on the value of R1 and the LEDs used). Make sure that you turn the volume down fully on your amplifier before you connect this circuit since the level of the output signal can vary significantly.

Internet Links
Demo film: http://youtu.
The version uses different LEDs and
4.7 μF for C2:

The voltages are generally in the range of 100–240 V (always expressed as root-mean-square voltage). The two commonly used frequencies are 50 Hz and 60 Hz.
Ohms Law and Power
  1. To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)
  2. To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)
  3. To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)
  4. To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)

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